Question

Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $32km$ above the earth's surface is (Assume the radius of the earth to be $6400km$ )

• A. $\text{0.99 }\text{g}$
• B. $\text{0.8}g$
• C. $\text{1.01}g$
• D. $\text{0.9}g$

Answer 1

Answer: (A)

Acceleration due to gravity at height $h$ is
$g^{\prime }=\frac{g}{{\left(1+\frac{h}{R_e}\right)}^2}=\frac{g}{{\left(1+\frac{32}{6400}\right)}^2}=\text{0.99}g$