Question

Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $32 \, km$ above the earth's surface is (Assume the radius of the earth to be $6400 \, km$ )

• A. $\text{0.99 }\textit{g}$
• B. $\text{0.8}g$
• C. $\text{1.01}g$
• D. $\text{0.9}g$

Answer 1

Answer: (A)

Acceleration due to gravity at height $h$ is
$g^{′}=\frac{g}{\left(1 + \frac{h}{R_{e}}\right)^{2}}=\frac{g}{\left(1 + \frac{32}{6400}\right)^{2}}=\text{0.99} \, g$