Tardigrade
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Tardigrade
Question
Mathematics
ABC is a triangle and P is any point on BC such that PQ is the resultant of the vectors AP , PB and PC , then
Q.
A
BC
is a triangle and
P
is any point on
BC
such that
PQ
is the resultant of the vectors
A
P
,
PB
and
PC
, then
1894
235
Vector Algebra
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A
the position of
Q
depends on position of
P
25%
B
Q
is a fixed point
37%
C
Q lies on
A
B
or
A
C
29%
D
None of these
9%
Solution:
We have
⇒
PQ
=
A
P
+
PB
+
PC
⇒
PQ
=
A
B
+
PC
⇒
A
B
=
PQ
−
PC
=
PQ
+
CP
=
CP
+
PQ
=
CQ
∴
A
B
=
CQ
and
A
B
∣∣
CQ
∴
A
BQC
is a parallelogram,
∴
is a fixed point