AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattices is

Question

AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattices is (A) 250 pm (B) 200 pm (C) 300 pm (D) 335 pm

Tardigrade Admin · Accepted Answer

For BCC lattice body diagonal = a √ 3 . The distance between the two oppositely charged ions = (a/2) √3 = (387 × 1.732/2) = 335 pm

Q. $A B$ crystallizes in a body centred cubic lattice with edge length 'a' equal to $387 p m$ . The distance between two oppositely charged ions in the lattices is

250 pm

200 pm

300 pm

335 pm

For $BCC$ lattice body diagonal $= a 3$ .
The distance between the two oppositely charged ions $= \frac{a}{2} 3$
$= \frac{387 \times 1.732}{2} = 335 p m$

Q. AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387pm. The distance between two oppositely charged ions in the lattices is