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  4. AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositely charged ions in the lattices is

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Q. $AB$ crystallizes in a body centred cubic lattice with edge length 'a' equal to $387 \,pm$. The distance between two oppositely charged ions in the lattices is

AIPMTAIPMT 2010The Solid State

Solution:

For $BCC$ lattice body diagonal $= a \sqrt{ 3}$ .
The distance between the two oppositely charged ions $ = \frac{a}{2} \sqrt{3}$
$ = \frac{387 \times 1.732}{2} = 335\, pm $