A Zener diode is connected to a battery and a load as shown below: The currents I, IZ and IL are respectively

Question

A Zener diode is connected to a battery and a load as shown below: The currents I, IZ and IL are respectively <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-biw5tzx02cfj.png" /> (A) 12.5 mA, 7.5 mA, 5 mA (B) 15 mA, 7.5 mA, 7.5 mA (C) 12.5 mA, 5 mA, 7.5 mA (D) 15 mA, 5 mA, 10 mA

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-biw5tzx0b2lv.png" /> I L =( V AB / R L )=(10/2000)=5 mA I =(60-10/4000)=(50/4000)=12 ⋅ 5 mA I = I L + I Z ∴ I Z = I - I L =7 ⋅ 5 mA Hence, 12.5 mA , 7.5 mA , 5 mA

Q. A Zener diode is connected to a battery and a load as shown below: The currents I, I_Z and I_L are respectively

12.5 mA, 7.5 mA, 5 mA

15 mA, 7.5 mA, 7.5 mA

12.5 mA, 5 mA, 7.5 mA

15 mA, 5 mA, 10 mA

$I_{L} = \frac{V _{A B}}{R _{L}} = \frac{10}{2000} = 5 m A$
$I = \frac{60 - 10}{4000} = \frac{50}{4000} = 12 \cdot 5 m A$
$I = I_{L} + I_{Z} ∴ I_{Z} = I - I_{L} = 7 \cdot 5 m A$
Hence, $12.5 m A, 7.5 m A, 5 m A$

Q. A Zener diode is connected to a battery and a load as shown below: The currents I, IZ and IL are respectively