A Zener diode, having breakdown voltage equal to 15 V is used in a voltage regulator circuit shown in the figure. The current through the diode is

Question

A Zener diode, having breakdown voltage equal to 15 V is used in a voltage regulator circuit shown in the figure. The current through the diode is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-bvbtaxajclvvtduw.jpg" /> (A) 10mA (B) 15 mA (C) 20 mA (D) 5 mA

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-bvbtaxajclvvnqy6.jpg" /> For R=1kΩ i1=(15/1)mA=15mA For R=250 Ω i250=(20 - 15/250)=(5/250) =(20/1000)=20 mA iz e n e r=20-15 =5 mA

Q. A Zener diode, having breakdown voltage equal to $15 V$ is used in a voltage regulator circuit shown in the figure. The current through the diode is

$10 m A$

$15 m A$

$20 m A$

$5 m A$

For $R = 1 k Ω$
$i_{1} = \frac{15}{1} m A = 15 m A$
For $R = 250 Ω$
$i_{250} = \frac{20 - 15}{250} = \frac{5}{250}$
$= \frac{20}{1000} = 20 m A$
$i_{ze n er} = 20 - 15$
$= 5 m A$

Q. A Zener diode, having breakdown voltage equal to 15V is used in a voltage regulator circuit shown in the figure. The current through the diode is

10mA

15mA

20mA

5mA