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Q. A Zener diode, having breakdown voltage equal to $15 \, V$ is used in a voltage regulator circuit shown in the figure. The current through the diode is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
For $R=1k\Omega $
$i_{1}=\frac{15}{1}mA=15mA$
For $R=250 \, \Omega$
$i_{250}=\frac{20 - 15}{250}=\frac{5}{250}$
$=\frac{20}{1000}=20 \, mA$
$i_{z e n e r}=20-15$
$=5 \, mA$