A wire is sliding on two parallel conducting rails placed at a separation of 1 m as shown in the figure. Magnetic field of 2 T exists in a direction perpendicular to the rails. The necessary force required to keep the wire moving with a constant velocity of 1 cm / s is n × 10-4 N. Find n.

Question

A wire is sliding on two parallel conducting rails placed at a separation of 1 m as shown in the figure. Magnetic field of 2 T exists in a direction perpendicular to the rails. The necessary force required to keep the wire moving with a constant velocity of 1 cm / s is n × 10-4 N. Find n. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

F=(B2 v l2/R)=(4 × 10-2 × 1/50) =8 × 10-4 N

Q. A wire is sliding on two parallel conducting rails placed at a separation of 1m as shown in the figure. Magnetic field of 2T exists in a direction perpendicular to the rails. The necessary force required to keep the wire moving with a constant velocity of 1cm/s is n×10−4N. Find n.

F=RB2vl2​=504×10−2×1​ =8×10−4N

$F = \frac{B ^{2} v l ^{2}}{R} = \frac{4 \times 1 0 ^{- 2} \times 1}{50}$
$= 8 \times 1 0^{- 4} N$