A wire is 4 m long and has a mass 0.2 kg . The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and forth along the cord in 0.8 sec . The tension in the cord will be

Question

A wire is 4 m long and has a mass 0.2 kg . The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and forth along the cord in 0.8 sec . The tension in the cord will be (A) 80 N (B) 160 N (C) 240 N (D) 320 N

Tardigrade Admin · Accepted Answer

4 trips means 32 m <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-nlwr93w6ucrc.png" /> Wave speed is, v=(d/t)=(32/0.8)=40 m s- 1 v=√(T/μ ) Therefore, tension in the cord is, T=μ v2 T=(0.2/4)× (40)2=(2 × 16 × 10/4) T=80 N

Q. A wire is $4 m$ long and has a mass $0.2 k g$ . The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and forth along the cord in $0.8 sec$ . The tension in the cord will be

$80 N$

$160 N$

$240 N$

$320 N$

$4$ trips means $32 m$

Wave speed is,
$v = \frac{d}{t} = \frac{32}{0.8} = 40 m s^{- 1}$
$v = \frac{T}{μ}$
Therefore, tension in the cord is,
$T = μ v^{2}$
$T = \frac{0.2}{4} \times (40)^{2} = \frac{2 \times 16 \times 10}{4}$
$T = 80 N$

Q. A wire is 4m long and has a mass 0.2kg . The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and forth along the cord in 0.8sec . The tension in the cord will be

80N

160N

240N

320N