Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A wire is $4 \, m$ long and has a mass $0.2 \, kg$ . The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and forth along the cord in $0.8 \, sec$ . The tension in the cord will be

NTA AbhyasNTA Abhyas 2020Waves

Solution:

$4$ trips means $32 \, m$
Solution
Wave speed is,
$v=\frac{d}{t}=\frac{32}{0.8}=40 \, m \, s^{- 1}$
$v=\sqrt{\frac{T}{\mu }}$
Therefore, tension in the cord is,
$T=\mu v^{2}$
$T=\frac{0.2}{4}\times \left(40\right)^{2}=\frac{2 \times 16 \times 10}{4}$
$T=80 \, N$