A wire has resistance 12 Ω . It is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is:

Question

A wire has resistance 12 Ω . It is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is: (A)  12 Ω  (B)  24 Ω  (C)  6 Ω  (D)  3 Ω

Tardigrade Admin · Accepted Answer

Resistance of wire is 12 ohm. Therefore, resistance of each semicircle =6 ohm Two resistances are in parallel. Their equivalent resistance =(6 × 6/6+6)=3 ohm

Q. A wire has resistance $12 Ω$ . It is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is:

$12 Ω$

$24 Ω$

$6 Ω$

$3 Ω$

Resistance of wire is $12 o hm$ .
Therefore, resistance of each semicircle $= 6 o hm$
Two resistances are in parallel.
Their equivalent resistance $= \frac{6 \times 6}{6 + 6} = 3 o hm$

Q. A wire has resistance 12Ω . It is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is:

12Ω

24Ω

6Ω

3Ω