A weightless rod is acted upon by two upward parallel forces of 2 N and 4 N at ends A and B respectively. The total length of the operatornamerod A B=3 m . To keep the rod in equilibrium a force of 6 N should act in the following manner.

Question

A weightless rod is acted upon by two upward parallel forces of 2 N and 4 N at ends A and B respectively. The total length of the operatornamerod A B=3 m . To keep the rod in equilibrium a force of 6 N should act in the following manner. (A) Downwards at any point between A and B (B) Downwards at the mid point of A B (C) Downwards at a point C such that A C=1 m (D) Downwards at a point D such that B D=1 m

Tardigrade Admin · Accepted Answer

2(3-x)=4 x ⇒ x=1 m <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b01ed4e874a59bba05996f4519d45cf9-.png" />

Q. A weightless rod is acted upon by two upward parallel forces of $2 N$ and $4 N$ at ends $A$ and $B$ respectively. The total length of the $rod A B = 3 m .$ To keep the rod in equilibrium a force of $6 N$ should act in the following manner.

Downwards at any point between $A$ and $B$

Downwards at the mid point of $A B$

Downwards at a point $C$ such that $A C = 1 m$

Downwards at a point $D$ such that $B D = 1 m$

$2 (3 - x) = 4 x \Rightarrow x = 1 m$

Q. A weightless rod is acted upon by two upward parallel forces of 2N and 4N at ends A and B respectively. The total length of the rodAB=3m. To keep the rod in equilibrium a force of 6N should act in the following manner.

Downwards at any point between A and B

Downwards at the mid point of AB

Downwards at a point C such that AC=1m

Downwards at a point D such that BD=1m