Question

A weightless rod is acted upon by two upward parallel forces of $2 N$ and $4 N$ at ends $A$ and $B$ respectively. The total length of the $\operatorname{rod} A B=3 m .$ To keep the rod in equilibrium a force of $6 N$ should act in the following manner.

• A. Downwards at any point between $A$ and $B$
• B. Downwards at the mid point of $A B$
• C. Downwards at a point $C$ such that $A C=1 m$
• D. Downwards at a point $D$ such that $B D=1 m$

Answer 1

Answer: (D)

$2(3-x)=4 x \Rightarrow x=1 m$