A vessel of depth 2h is half filled with a liquid of refractive index 2√2 and the upper half with another liquid of refractive index √2 . The liquids are immiscible. The apparent depth of the inner surface of the bottom of the vessel will be

Question

A vessel of depth 2h is half filled with a liquid of refractive index 2√2 and the upper half with another liquid of refractive index √2 . The liquids are immiscible. The apparent depth of the inner surface of the bottom of the vessel will be (A) (h/√2) (B) (h/2 (√2 + 1)) (C) (h/3 √2) (D) (3 √2 h/4)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-5lxi4hgkm6by969q.jpg" /> d=(h/√2)+(h/2 √2) ⇒ d=(h/√2)× (3/2)=(3 √2 h/4)

Q. A vessel of depth $2 h$ is half filled with a liquid of refractive index $22$ and the upper half with another liquid of refractive index $2$ . The liquids are immiscible. The apparent depth of the inner surface of the bottom of the vessel will be

$\frac{h}{2}$

$\frac{h}{2 ( 2 + 1 )}$

$\frac{h}{3 2}$

$\frac{3 2 h}{4}$

$d = \frac{h}{2} + \frac{h}{2 2}$
$\Rightarrow d = \frac{h}{2} \times \frac{3}{2} = \frac{3 2 h}{4}$

Q. A vessel of depth 2h is half filled with a liquid of refractive index 22​ and the upper half with another liquid of refractive index 2​ . The liquids are immiscible. The apparent depth of the inner surface of the bottom of the vessel will be

2​h​

2(2​+1)h​

32​h​

432​h​