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Q. A vessel of depth $2h$ is half filled with a liquid of refractive index $2\sqrt{2}$ and the upper half with another liquid of refractive index $\sqrt{2}$ . The liquids are immiscible. The apparent depth of the inner surface of the bottom of the vessel will be

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$d=\frac{h}{\sqrt{2}}+\frac{h}{2 \sqrt{2}}$
$\Rightarrow d=\frac{h}{\sqrt{2}}\times \frac{3}{2}=\frac{3 \sqrt{2} h}{4}$