A vessel contains 110 g of water. The heat capacity of the vessel is equal to 10 g of water. The initial temperature of water in vessel is 10° C. If 220 g of hot water at 70° C is poured in the vessel, the final temperature neglecting radiation loss, will be

Question

A vessel contains 110 g of water. The heat capacity of the vessel is equal to 10 g of water. The initial temperature of water in vessel is 10° C. If 220 g of hot water at 70° C is poured in the vessel, the final temperature neglecting radiation loss, will be (A) 70° C (B) 80° C (C) 60° C (D) 50° C

Tardigrade Admin · Accepted Answer

Let final temperature of water be θ Heat taken = Heat given 110 × 1(θ-10)+10(θ-10) =220 × 1(70-θ) ⇒ θ=48.8° C =50° C

Q. A vessel contains $110 g$ of water. The heat capacity of the vessel is equal to $10 g$ of water. The initial temperature of water in vessel is $1 0^{\circ} C$ . If $220 g$ of hot water at $7 0^{\circ} C$ is poured in the vessel, the final temperature neglecting radiation loss, will be

$7 0^{\circ} C$

$8 0^{\circ} C$

$6 0^{\circ} C$

$5 0^{\circ} C$

Let final temperature of water be $θ$
Heat taken $=$ Heat given $110 \times 1 (θ - 10) + 10 (θ - 10)$
$= 220 \times 1 (70 - θ)$
$\Rightarrow θ = 48. 8^{\circ} C = 5 0^{\circ} C$

Q. A vessel contains 110g of water. The heat capacity of the vessel is equal to 10g of water. The initial temperature of water in vessel is 10∘C. If 220g of hot water at 70∘C is poured in the vessel, the final temperature neglecting radiation loss, will be

70∘C

80∘C

60∘C

50∘C