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Q. A vessel contains $110\, g$ of water. The heat capacity of the vessel is equal to $10\, g$ of water. The initial temperature of water in vessel is $10^{\circ} C$. If $220\, g$ of hot water at $70^{\circ} C$ is poured in the vessel, the final temperature neglecting radiation loss, will be

Thermal Properties of Matter

Solution:

Let final temperature of water be $\theta$
Heat taken $=$ Heat given $110 \times 1(\theta-10)+10(\theta-10)$
$=220 \times 1(70-\theta)$
$\Rightarrow \theta=48.8^{\circ} C =50^{\circ} C$