A vessel containing water has area of cross- section 16 cm 2 . A small square hole of side 1 cm is at the bottom. What will be the time taken by the water to empty the vessel if vessel is filled up to the height of 32 cm ? ( g =9.8 m / s -2)

Question

A vessel containing water has area of cross- section 16 cm 2 . A small square hole of side 1 cm is at the bottom. What will be the time taken by the water to empty the vessel if vessel is filled up to the height of 32 cm ? ( g =9.8 m / s -2) (A) 3 sec (B) 5 sec (C) 4 sec (D) 8 sec

Tardigrade Admin · Accepted Answer

t=(A/A0) √(2 H/g)=(16 × 10-4/1 × 10-4) √(2 × 32 × 10-2/9.8) t=(16 × 8 × 10-1/√0.8)=(12.8/313)=4.08 sec

Q. A vessel containing water has area of cross- section $16 c m^{2}$ . A small square hole of side $1 c m$ is at the bottom. What will be the time taken by the water to empty the vessel if vessel is filled up to the height of $32 c m$ ? $(g = 9.8 m / s^{- 2})$

$3 sec$

$5 sec$

$4 sec$

$8 sec$

$t = \frac{A}{A _{0}} \frac{2 H}{g} = \frac{16 \times 1 0 ^{- 4}}{1 \times 1 0 ^{- 4}} \frac{2 \times 32 \times 1 0 ^{- 2}}{9.8}$
$t = \frac{16 \times 8 \times 1 0 ^{- 1}}{0.8} = \frac{12.8}{313} = 4.08 sec$

Q. A vessel containing water has area of cross- section 16cm2. A small square hole of side 1cm is at the bottom. What will be the time taken by the water to empty the vessel if vessel is filled up to the height of 32cm ? (g=9.8m/s−2)

3sec

5sec

4sec

8sec