Question

A vessel contain a liquid has a constant acceleration $19.6m/s^2$ in horizontal direction. The free surface of water get sloped with horizontal at angle

• A. ${\tan }^{-1}\left[\frac{1}{2}\right]$
• B. ${\sin }^{-1}\left[\frac{1}{\sqrt{3}}\right]$
• C. ${\tan }^{-1}[\sqrt{2}]$
• D. ${\sin }^{-1}\left[\frac{2}{\sqrt{5}}\right]$

Answer 1

Answer: (D)

$\tan \theta =\frac{a}{g}=\frac{19.6}{9.8}=2$
$\tan \theta =2$
$\Rightarrow \sin \theta =\frac{2}{\sqrt{5}}$
$\Rightarrow \theta ={\sin }^{-1}\left[\frac{2}{\sqrt{5}}\right]$