Question

A vessel contain a liquid has a constant acceleration $19.6\, m / s ^{2}$ in horizontal direction. The free surface of water get sloped with horizontal at angle

• A. $\tan ^{-1}\left[\frac{1}{2}\right]$
• B. $\sin ^{-1}\left[\frac{1}{\sqrt{3}}\right]$
• C. $\tan ^{-1}[\sqrt{2}]$
• D. $\sin ^{-1}\left[\frac{2}{\sqrt{5}}\right]$

Answer 1

Answer: (D)

$\tan \theta=\frac{a}{g}=\frac{19.6}{9.8}=2$
$\tan \theta=2$
$\Rightarrow \sin \theta=\frac{2}{\sqrt{5}}$
$\Rightarrow \theta=\sin ^{-1}\left[\frac{2}{\sqrt{5}}\right]$