A vernier calipers has 1 mm marks on the main scale. It has 20 equal divisions on the vernier scale which match with 16 main scale divisions. For this vernier calipeis, the least count is

Question

A vernier calipers has 1 mm marks on the main scale. It has 20 equal divisions on the vernier scale which match with 16 main scale divisions. For this vernier calipeis, the least count is (A) 0.02 mm (B) 0.05 mm (C) 0.1 mm (D) 0.2 mm

Tardigrade Admin · Accepted Answer

Least count of vernier calipers LC =1 MSD -1 VSD =( text Smallest division on main scale / text Number of divisions on vernier scale ) 20 divisions of vernier scale =16 divisions of main scale ∴ 1 VSD =(16/20) mm =0.8 mm ∴ LC =1 MSD -1 VSD =1 mm -0.8 mm =0.2 mm

Q. A vernier calipers has $1 mm$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier calipeis, the least count is

0.02 mm

0.05 mm

0.1 mm

0.2 mm

Least count of vernier calipers
$L C = 1 MS D - 1 V S D$
$= \frac{Smallest division on main scale}{Number of divisions on vernier scale}$
$20$ divisions of vernier scale $= 16$ divisions of main scale
$∴ 1 V S D = \frac{16}{20} mm = 0.8 mm$
$∴ L C = 1 MS D - 1 V S D$
$= 1 mm - 0.8 mm = 0.2 mm$

Q. A vernier calipers has 1mm marks on the main scale. It has 20 equal divisions on the vernier scale which match with 16 main scale divisions. For this vernier calipeis, the least count is