A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (in text ms-1) is:

Question

A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (in text ms-1) is: (A) 84 (B) 42 (C) 21 (D) 10.5

Tardigrade Admin · Accepted Answer

Fundamental frequency of string text= GCF of the successive harmonics of frequencise 70 Hz and 84 Hz ∴ n=14 Hz ⇒ (v/2l)=1.4 ⇒ v=2× 1.5× 14 =42 m/s

Q. A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string $(in m s^{- 1})$ is:

84

42

21

10.5

Fundamental frequency of string $= GCF$ of the successive harmonics of frequencise 70 Hz and 84 Hz $∴$ $n = 14 Hz$ $\Rightarrow$ $\frac{v}{2 l} = 1.4$ $\Rightarrow$ $v = 2 \times 1.5 \times 14$ $= 42 m / s$

Q. A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (inms−1) is:

84

42

21

10.5

Fundamental frequency of string = GCF of the successive harmonics of frequencise 70 Hz and 84 Hz ∴ n=14Hz ⇒ 2lv​=1.4 ⇒ v=2×1.5×14 =42m/s

Q. A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string $(in m s^{- 1})$ is:

Fundamental frequency of string $= GCF$ of the successive harmonics of frequencise 70 Hz and 84 Hz $∴$ $n = 14 Hz$ $\Rightarrow$ $\frac{v}{2 l} = 1.4$ $\Rightarrow$ $v = 2 \times 1.5 \times 14$ $= 42 m / s$