1. Tardigrade
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  4. A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string (in text ms-1) is:

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Q. A uniform string of length 1.5 m has two successive harmonics of frequencies 70 Hz and 84 Hz. The speed of the wave in the string $ (in\text{ }m{{s}^{-1}}) $ is:

EAMCETEAMCET 2006Electromagnetic Waves

Solution:

Fundamental frequency of string $ \text{= GCF} $ of the successive harmonics of frequencise 70 Hz and 84 Hz $ \therefore $ $ n=14\,Hz $ $ \Rightarrow $ $ \frac{v}{2l}=1.4 $ $ \Rightarrow $ $ v=2\times 1.5\times 14 $ $ =42\,m/s $