A uniform meter scale of mass 1 kg is placed on a table such that a part of the scale is beyond the edge. If a body of mass 0.25 kg is hung at the end of the scale then the minimum length of scale that should lie on the table so that it does not tilt is

Question

A uniform meter scale of mass 1 kg is placed on a table such that a part of the scale is beyond the edge. If a body of mass 0.25 kg is hung at the end of the scale then the minimum length of scale that should lie on the table so that it does not tilt is (A) 90cm (B) 80 cm (C) 70 cm (D) 60 cm

Tardigrade Admin · Accepted Answer

If the distance from one end is x then (50 - x)1=x(0.25)=(x/4) 200-4x=x⇒ x=40 cm ∴ Length on the table =100-40=60 cm

Q. A uniform meter scale of mass $1 k g$ is placed on a table such that a part of the scale is beyond the edge. If a body of mass $0.25 k g$ is hung at the end of the scale then the minimum length of scale that should lie on the table so that it does not tilt is

$90 c m$

$80 c m$

$70 c m$

$60 c m$

If the distance from one end is x then
$(50 - x) 1 = x (0.25) = \frac{x}{4}$
$200 - 4 x = x \Rightarrow x = 40 c m$
$∴$ Length on the table $= 100 - 40 = 60 c m$

Q. A uniform meter scale of mass 1kg is placed on a table such that a part of the scale is beyond the edge. If a body of mass 0.25kg is hung at the end of the scale then the minimum length of scale that should lie on the table so that it does not tilt is

90cm

80cm

70cm

60cm