A uniform metallic wire has a resistance of 18 Ω and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is :

Question

A uniform metallic wire has a resistance of 18 Ω and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is : (A)  8 Ω  (B)  12 Ω  (C)  4 Ω  (D)  2 Ω

Tardigrade Admin · Accepted Answer

Req between any two vertex will be (1/Req) = (1/12) + (1/6) ⇒ Req = 4 Ω

Q. A uniform metallic wire has a resistance of $18 Ω$ and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is :

$8 Ω$

$12 Ω$

$4 Ω$

$2 Ω$

$R_{e q}$ between any two vertex will be
$\frac{1}{R _{e q}} = \frac{1}{12} + \frac{1}{6} \Rightarrow R_{e q} = 4Ω$

Q. A uniform metallic wire has a resistance of 18Ω and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is :

8Ω

12Ω

4Ω

2Ω