Q. A uniform metallic wire has a resistance of $18 \; \Omega$ and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is :
Solution:
$R_{eq}$ between any two vertex will be
$\frac{1}{R_{eq}} = \frac{1}{12} + \frac{1}{6} \; \Rightarrow \; R_{eq} = 4 \Omega$
