A uniform metal chain is placed on a rough table such that one end of chain hangs downover the edge of the table. When two - third of its chain length hangs over the edge the chain start sliding. Then the coefficient of static friction is

Question

A uniform metal chain is placed on a rough table such that one end of chain hangs downover the edge of the table. When two - third of its chain length hangs over the edge the chain start sliding. Then the coefficient of static friction is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

μs=( text Length of chain hanging from the table / text length of chain lying on the table ) μ s =(2 / 3/1-(2)3)=2

Q. A uniform metal chain is placed on a rough table such that one end of chain hangs downover the edge of the table. When two - third of its chain length hangs over the edge the chain start sliding. Then the coefficient of static friction is

1

2

3

4

$μ_{s} = \frac{Length of chain hanging from the table}{length of chain lying on the table}$
$μ_{s} = \frac{2/3}{1 - \frac{2}{3}} = 2$

Q. A uniform metal chain is placed on a rough table such that one end of chain hangs downover the edge of the table. When two - third of its chain length hangs over the edge the chain start sliding. Then the coefficient of static friction is

1

2

3

4

μs​= length of chain lying on the table Length of chain hanging from the table ​ μs​=1−32​2/3​=2

$μ_{s} = \frac{Length of chain hanging from the table}{length of chain lying on the table}$
$μ_{s} = \frac{2/3}{1 - \frac{2}{3}} = 2$