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Q. A uniform metal chain is placed on a rough table such that one end of chain hangs downover the edge of the table. When two - third of its chain length hangs over the edge the chain start sliding. Then the coefficient of static friction is

Laws of Motion

Solution:

$\mu_{s}=\frac{\text { Length of chain hanging from the table }}{\text { length of chain lying on the table }}$
$\mu_{ s }=\frac{2 / 3}{1-\frac{2}{3}}=2$