A typical nuclear fusion reaction is given by:- 1H2+ 1H2 arrow 1H3+ 1H1+4.0MeV 1H2+ 1H2 arrow 2He4+ 0n1+17.6MeV The net result of two reactions is: 3× 1H2 arrow 2He4+ 0n1+ 1H1+21.6MeV The energy released per nucleon of the reactant, in the above thermonuclear reaction is:-

Question

A typical nuclear fusion reaction is given by:- 1H2+ 1H2 arrow 1H3+ 1H1+4.0MeV 1H2+ 1H2 arrow 2He4+ 0n1+17.6MeV The net result of two reactions is: 3× 1H2 arrow 2He4+ 0n1+ 1H1+21.6MeV The energy released per nucleon of the reactant, in the above thermonuclear reaction is:- (A) 1.8MeV (B) 3.6MeV (C) 7.2MeV (D) 21.6MeV

Tardigrade Admin · Accepted Answer

31H2 arrow 2He4+ 0n1+ 1H1+21.6MeV energy released per nucleon =(21 . 6/6)=3.6MeV

$1.8 M e V$

$3.6 M e V$

$7.2 M e V$

$21.6 M e V$

$3_{1} H^{2} \to_2 H e^{4} +_0 n_{1} +_1 H_{1} + 21.6 M e V$
energy released per nucleon
$= \frac{21.6}{6} = 3.6 M e V$

1.8MeV

3.6MeV

7.2MeV

21.6MeV

31​H2→_2He4+_0n1​+_1H1​+21.6MeV energy released per nucleon =621.6​=3.6MeV

$1.8 M e V$

$3.6 M e V$

$7.2 M e V$

$21.6 M e V$

$3_{1} H^{2} \to_2 H e^{4} +_0 n_{1} +_1 H_{1} + 21.6 M e V$
energy released per nucleon
$= \frac{21.6}{6} = 3.6 M e V$