Question

A typical nuclear fusion reaction is given by:-
$\_{1}^{}H_{}^{2}+\_{1}^{}H_{}^{2} \rightarrow \_{1}^{}H_{}^{3}+\_{1}^{}H_{}^{1}+4.0MeV$
$\_{1}^{}H_{}^{2}+\_{1}^{}H_{}^{2} \rightarrow \_{2}^{}He^{4}+\_{0}^{}n_{}^{1}+17.6MeV$
The net result of two reactions is:
$3\times \_{1}^{}H_{}^{2} \rightarrow \_{2}^{}He^{4}+\_{0}^{}n_{}^{1}+\_{1}^{}H_{}^{1}+21.6MeV$
The energy released per nucleon of the reactant, in the above thermonuclear reaction is:-

• A. $1.8MeV$
• B. $3.6MeV$
• C. $7.2MeV$
• D. $21.6MeV$

Answer 1

Answer: (B)

$3_{1}H^{2} \rightarrow \_{2}^{}He^{4}+\_{0}^{}n_{}^{1}+\_{1}^{}H_{}^{1}+21.6MeV$
energy released per nucleon
$=\frac{21 . 6}{6}=3.6MeV$