A travelling microscope has a main scale graduated in (1/2) mm. 50 vernier divisions coincide with 49 main scale divisions. What will be the reading if the main scale reads 7.45 cm and the 29th division of the vernier coincides with the main scale division ?

Question

A travelling microscope has a main scale graduated in (1/2) mm. 50 vernier divisions coincide with 49 main scale divisions. What will be the reading if the main scale reads 7.45 cm and the 29th division of the vernier coincides with the main scale division ? (A) 7.459 cm (B) 7.453 cm (C) 7.479 cm (D) 7.48 cm

Tardigrade Admin · Accepted Answer

Least count = 1 MSD - 1 VSD =0.5 mm-0.5 mm-((49/50))(0.5 mm) =0.001 cm Reading = 7.45 + 29 × 0.001 = 7.479 cm

Q. A travelling microscope has a main scale graduated in $\frac{1}{2} mm$ . $50$ vernier divisions coincide with $49$ main scale divisions. What will be the reading if the main scale reads $7.45 c m$ and the $2 9^{t h}$ division of the vernier coincides with the main scale division ?

$7.459 c m$

$7.453 c m$

$7.479 c m$

$7.48 c m$

Least count $= 1 MS D - 1 V S D$
$= 0.5 mm - 0.5 mm - (\frac{49}{50}) (0.5 mm)$
$= 0.001 c m$
Reading $= 7.45 + 29 \times 0.001 = 7.479 c m$

Q. A travelling microscope has a main scale graduated in 21​mm. 50 vernier divisions coincide with 49 main scale divisions. What will be the reading if the main scale reads 7.45cm and the 29th division of the vernier coincides with the main scale division ?

7.459cm

7.453cm

7.479cm

7.48cm