A transistor has a current amplification factor of 60 . In a CE amplifier, input resistance is 1 k Ω and output voltage is 0.01 V . The transconductance is (in SI units)

Question

A transistor has a current amplification factor of 60 . In a CE amplifier, input resistance is 1 k Ω and output voltage is 0.01 V . The transconductance is (in SI units) (A) 10-5 (B) 6 × 10-2 (C) 6 × 104 (D) 10

Tardigrade Admin · Accepted Answer

β=(Δ IC/Δ lB)=60 Ri=1 k Ω, V0=0.01 V g m=(β/Ri)=(60/1 × 103) =6 × 10-2

Q. A transistor has a current amplification factor of $60$ . In a CE amplifier, input resistance is $1 k Ω$ and output voltage is $0.01 V .$ The transconductance is (in SI units)

$1 0^{- 5}$

$6 \times 1 0^{- 2}$

$6 \times 1 0^{4}$

$10$

$β = \frac{Δ I _{C}}{Δ l _{B}} = 60$
$R_{i} = 1 k Ω, V_{0} = 0.01 V$
$g m = \frac{β}{R _{i}} = \frac{60}{1 \times 1 0 ^{3}}$
$= 6 \times 1 0^{- 2}$

Q. A transistor has a current amplification factor of 60 . In a CE amplifier, input resistance is 1kΩ and output voltage is 0.01V. The transconductance is (in SI units)

10−5

6×10−2

6×104

10