Question

A transistor has a current amplification factor of $60$ . In a CE amplifier, input resistance is $1 \,k \Omega$ and output voltage is $0.01\, V .$ The transconductance is (in SI units)

• A. $10^{-5}$
• B. $6 \times 10^{-2}$
• C. $6 \times 10^{4}$
• D. $10$

Answer 1

Answer: (B)

$\beta=\frac{\Delta I_{C}}{\Delta l_{B}}=60 $
$R_{i}=1\, k \Omega, V_{0}=0.01 \,V$
$g m=\frac{\beta}{R_{i}}=\frac{60}{1 \times 10^{3}}$
$=6 \times 10^{-2}$