A transformer with turns ratio (N1/N2)=(50/1) is connected to a 120 volt AC supply. If primary and secondary circuit resistance are 1.5 k Ω and 1 Ω respectively then find out power out put

Question

A transformer with turns ratio (N1/N2)=(50/1) is connected to a 120 volt AC supply. If primary and secondary circuit resistance are 1.5 k Ω and 1 Ω respectively then find out power out put (A) 5.76 W (B) 11.4 W (C) 2.89 W (D) 7.56 W

Tardigrade Admin · Accepted Answer

(V2/V 1)=(N2/N1) (V2/120)=(1/50) V2=(12/5) Let transformer ideal P text in =P text out P text out =(V22/R2)=(((12/5))2/10)=(144/25 × 1) =(144/25)=5.76 W

Q. A transformer with turns ratio $\frac{N _{1}}{N _{2}} = \frac{50}{1}$ is connected to a $120$ volt AC supply. If primary and secondary circuit resistance are $1.5 k Ω$ and $1 Ω$ respectively then find out power out put

5.76 W

11.4 W

2.89 W

7.56 W

$\frac{V _{2}}{V 1} = \frac{N _{2}}{N _{1}}$
$\frac{V _{2}}{120} = \frac{1}{50}$
$V_{2} = \frac{12}{5}$
Let transformer ideal
$P_{in} = P_{out}$
$P_{out} = \frac{V _{2}^{2}}{R _{2}} = \frac{( \frac{12}{5} ) ^{2}}{10} = \frac{144}{25 \times 1}$
$= \frac{144}{25} = 5.76 W$

Q. A transformer with turns ratio N2​N1​​=150​ is connected to a 120 volt AC supply. If primary and secondary circuit resistance are 1.5kΩ and 1Ω respectively then find out power out put