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Q. A transformer with turns ratio $\frac{N_{1}}{N_{2}}=\frac{50}{1}$ is connected to a $120$ volt AC supply. If primary and secondary circuit resistance are $1.5\, k \Omega$ and $1\,\Omega$ respectively then find out power out put

AIIMSAIIMS 2019

Solution:

$\frac{V_{2}}{V 1}=\frac{N_{2}}{N_{1}} $
$\frac{V_{2}}{120}=\frac{1}{50} $
$V_{2}=\frac{12}{5}$
Let transformer ideal
$P_{\text {in }}=P_{\text {out }}$
$P_{\text {out }}=\frac{V_{2}^{2}}{R_{2}}=\frac{\left(\frac{12}{5}\right)^{2}}{10}=\frac{144}{25 \times 1} $
$=\frac{144}{25}=5.76 \,W$