A thin plastic ring of radius R carries a charge q uniformly spread over the entire ring. The ring is rotating with angular velocity ω about its axis. The magnetic induction at the centre of the ring is

Question

A thin plastic ring of radius R carries a charge q uniformly spread over the entire ring. The ring is rotating with angular velocity ω about its axis. The magnetic induction at the centre of the ring is (A) (μ 0 q ω /2 π R) (B) (μ 0 q ω /π R) (C) (μ 0 q ω /4 π R) (D) zero

Tardigrade Admin · Accepted Answer

Due to charge q moving on circular path Bc e n t r e=(Âµ0 I/2 R)=(Âµ0 q f/2 R)=(Âµ0 q ω /4 π R)

Q. A thin plastic ring of radius $R$ carries a charge $q$ uniformly spread over the entire ring. The ring is rotating with angular velocity $ω$ about its axis. The magnetic induction at the centre of the ring is

$\frac{μ _{0} q ω}{2 π R}$

$\frac{μ _{0} q ω}{π R}$

$\frac{μ _{0} q ω}{4 π R}$

zero

Due to charge $q$ moving on circular path
$B_{ce n t re} = \frac{µ _{0} I}{2 R} = \frac{µ _{0} q f}{2 R} = \frac{µ _{0} q ω}{4 π R}$

Q. A thin plastic ring of radius R carries a charge q uniformly spread over the entire ring. The ring is rotating with angular velocity ω about its axis. The magnetic induction at the centre of the ring is

2πRμ0​qω​

πRμ0​qω​

4πRμ0​qω​