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Q. A thin plastic ring of radius $R$ carries a charge $q$ uniformly spread over the entire ring. The ring is rotating with angular velocity $\omega $ about its axis. The magnetic induction at the centre of the ring is

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

Due to charge $q$ moving on circular path
$B_{c e n t r e}=\frac{µ_{0} I}{2 R}=\frac{µ_{0} q f}{2 R}=\frac{µ_{0} q \omega }{4 \pi R}$