A taut string having tension 50 N and linear mass density 0.25 kg m- 1 is used inside a cart to generate a wave pulse starting at the left end. The velocity of cart so that the pulse remains stationary with respect to the ground is -α hatims- 1 . Write the value of 100α . (. Take, √2=1.414)

Question

A taut string having tension 50 N and linear mass density 0.25 kg m- 1 is used inside a cart to generate a wave pulse starting at the left end. The velocity of cart so that the pulse remains stationary with respect to the ground is -α hatims- 1 . Write the value of 100α . (. Take, √2=1.414) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

v=√(T/μ ) =√(50/0 . 25)=√200=10√2=14.14 m/s ∴ overset arrow VP= overset arrow VP C+ overset arrow VC G 0=14.14 hati+ overset arrow vC G overset arrow vCG=-14.14 hati m/s

Q. A taut string having tension 50N and linear mass density 0.25kgm−1 is used inside a cart to generate a wave pulse starting at the left end. The velocity of cart so that the pulse remains stationary with respect to the ground is −αi^ms−1 . Write the value of 100α. ( Take, 2​=1.414)

v=μT​​ =0.2550​​=200​=102​=14.14m/s ∴V→P​=V→PC​+V→CG​ 0=14.14i^+v→CG​ v→CG​=−14.14i^m/s

$v = \frac{T}{μ}$
$= \frac{50}{0.25} = 200 = 102 = 14.14 m / s$
$∴ V \to_{P} = V \to_{PC} + V \to_{CG}$
$0 = 14.14 \hat{i} + v \to_{CG}$
$v \to_{CG} = - 14.14 \hat{i} m / s$