A tall measuring jar contains ethyl alcohol of density 0.8 gm / cm 3. An iron ball is dropped into it and the level rises by 20 cm 3. The buoyant force acting on the ball is: (Take acceleration due to gravity to be 10 ms -2 )

Question

A tall measuring jar contains ethyl alcohol of density 0.8 gm / cm 3. An iron ball is dropped into it and the level rises by 20 cm 3. The buoyant force acting on the ball is: (Take acceleration due to gravity to be 10 ms -2 ) (A) 0.2N (B) 0.25 N (C) 0.16N (D) 1.6N

Tardigrade Admin · Accepted Answer

As the level rises by 20 cm 3 i.e., Volume of alcohol displaced by the iron ball =20 cm 3=20 × 10-6 m 3 Density in kg / m 3=0.8 × (10-3/10-6)=800 So, the force acting on the ball in upward direction =V × ρ × g beginarrayl =20 × 10-6 × 800 × 10 =0.16 N endarray

Q. A tall measuring jar contains ethyl alcohol of density 0.8gm/cm3. An iron ball is dropped into it and the level rises by 20cm3. The buoyant force acting on the ball is : (Take acceleration due to gravity to be 10ms−2 )

0.2N

0.25 N

0.16N

1.6N

As the level rises by 20cm3 i.e., Volume of alcohol displaced by the iron ball =20cm3=20×10−6m3 Density in kg/m3=0.8×10−610−3​=800 So, the force acting on the ball in upward direction =V×ρ×g =20×10−6×800×10=0.16N​

Q. A tall measuring jar contains ethyl alcohol of density $0.8 g m / c m^{3}$ . An iron ball is dropped into it and the level rises by $20 c m^{3}$ . The buoyant force acting on the ball is : (Take acceleration due to gravity to be $10 m s^{- 2}$ )