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Q. A tall measuring jar contains ethyl alcohol of density $0.8 gm / cm ^3$. An iron ball is dropped into it and the level rises by $20 cm ^3$. The buoyant force acting on the ball is : (Take acceleration due to gravity to be $10 ms ^{-2}$ )

Mechanical Properties of Fluids

Solution:

As the level rises by $20 cm ^3$
i.e., Volume of alcohol displaced by the iron ball $=20 cm ^3=20 \times 10^{-6} m ^3$
Density in $kg / m ^3=0.8 \times \frac{10^{-3}}{10^{-6}}=800$
So, the force acting on the ball in upward direction $=V \times \rho \times g$
$ \begin{array}{l} =20 \times 10^{-6} \times 800 \times 10 \\ =0.16 N \end{array} $