A system consisting of two masses connected by a massless rod lies along the x- axis. A 0.4 kg mass is at a distance x=2 text m while a 0.6 kg mass is at a distance x=7 text m . The. x- coordinate of the centre of mass is

Question

A system consisting of two masses connected by a massless rod lies along the x- axis. A 0.4 kg mass is at a distance x=2 text m while a 0.6 kg mass is at a distance x=7 text m . The. x- coordinate of the centre of mass is (A) 5 m (B) 3.5 m (C) 4.5 m (D) 4 m

Tardigrade Admin · Accepted Answer

The x- coordinate of centre of mass x=(m1x1+m2x2/m1+m2) Here, m1=0.4 kg,x1=2m m2=0.6 kg,x2=7m Hence, x=(0.4× 2+0.6× 7/0.4+0.6) x=5m

Q. A system consisting of two masses connected by a massless rod lies along the $x -$ axis. A 0.4 kg mass is at a distance $x = 2 m$ while a 0.6 kg mass is at a distance $x = 7 m$ . The. $x -$ coordinate of the centre of mass is

5 m

3.5 m

4.5 m

4 m

The $x -$ coordinate of centre of mass $x = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}}$ Here, $m_{1} = 0.4 k g, x_{1} = 2 m$ $m_{2} = 0.6 k g, x_{2} = 7 m$ Hence, $x = \frac{0.4 \times 2 + 0.6 \times 7}{0.4 + 0.6}$ $x = 5 m$

Q. A system consisting of two masses connected by a massless rod lies along the x− axis. A 0.4 kg mass is at a distance x=2m while a 0.6 kg mass is at a distance x=7m . The. x− coordinate of the centre of mass is

5 m

3.5 m

4.5 m

4 m

The x− coordinate of centre of mass x=m1​+m2​m1​x1​+m2​x2​​ Here, m1​=0.4kg,x1​=2m m2​=0.6kg,x2​=7m Hence, x=0.4+0.60.4×2+0.6×7​ x=5m

Q. A system consisting of two masses connected by a massless rod lies along the $x -$ axis. A 0.4 kg mass is at a distance $x = 2 m$ while a 0.6 kg mass is at a distance $x = 7 m$ . The. $x -$ coordinate of the centre of mass is

The $x -$ coordinate of centre of mass $x = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}}$ Here, $m_{1} = 0.4 k g, x_{1} = 2 m$ $m_{2} = 0.6 k g, x_{2} = 7 m$ Hence, $x = \frac{0.4 \times 2 + 0.6 \times 7}{0.4 + 0.6}$ $x = 5 m$