Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A system absorbs 10 kJ of heat and does 4 kJ of work. The internal energy of the system
Q. A system absorbs
10
k
J
of heat and does
4
k
J
of work. The internal energy of the system
2567
214
Thermodynamics
Report Error
A
Decreases by 6 kJ
29%
B
Increases by 6 kJ
41%
C
Decreases by 14 kJ
8%
D
Increases by 14 kJ
21%
Solution:
As per
I
s
t
law,
Δ
U
=
q
+
w
q
=
+
10
k
J
(heat is absorbed by the system)
w
=
−
4
k
J
(work is done by the system)
∴
Δ
U
=
q
+
w
=
10
−
4
k
J
=
+
6
k
J