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Q.
A system absorbs $10 \,kJ$ of heat and does $4\, kJ$ of work. The internal energy of the system
Thermodynamics
Solution:
As per $I ^{ st }$ law,
$\Delta U=q+w$
$q =+10\, kJ$ (heat is absorbed by the system)
$w=-4\, k\, J$ (work is done by the system)
$\therefore \Delta U=q+w=10-4 k\, J=+6\, kJ$