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Chemistry
A substance on treatment with dilute H 2 SO 4 liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. These reactions indicate the presence of
Q. A substance on treatment with dilute
H
2
S
O
4
liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. These reactions indicate the presence of
1845
225
The p-Block Elements - Part2
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A
C
O
3
2
−
B
S
2
−
C
S
O
3
2
−
D
N
O
2
−
Solution:
S
O
3
2
−
ion gives
S
O
2
with
H
2
S
O
4
which produces turbidity with baryta water.
S
O
3
2
−
+
H
2
S
O
4
⟶
S
O
4
2
−
+
H
2
O
+
S
O
2
↑
S
O
2
+
Baryta water
B
a
(
O
H
)
2
⟶
(Turbidity)
B
a
S
O
3
↓
+
H
2
O
S
O
2
also turns acidified dichromate solution green.
(
O
r
an
g
e
)
K
2
C
r
2
O
7
+
H
2
S
O
4
+
3
S
O
2
⟶
K
2
S
O
4
+
(
G
ree
n
)
C
r
2
(
S
O
4
)
3
+
H
2
O
Hence, the above reactions indicate the presence of
S
O
3
2
−
ions.