1. Tardigrade
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  4. A substance on treatment with dilute H 2 SO 4 liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. These reactions indicate the presence of

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Q. A substance on treatment with dilute $H _{2} SO _{4}$ liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. These reactions indicate the presence of

The p-Block Elements - Part2

Solution:

$SO _{3}^{2-}$ ion gives $SO _{2}$ with $H _{2} SO _{4}$ which produces turbidity with baryta water.

$SO _{3}^{2-}+ H _{2} SO _{4} \longrightarrow SO _{4}^{2-}+ H _{2} O + SO _{2} \uparrow$

$SO _{2}+ \underset{\text{Baryta water}}{Ba ( OH )_{2}} \longrightarrow \underset{\text{(Turbidity) }}{BaSO _{3}} \downarrow+ H _{2} O$

$SO _{2}$ also turns acidified dichromate solution green.

$\underset{{(Orange) }}{K _{2} Cr _{2} O _{7}}+ H _{2} SO _{4}+3 SO _{2} \longrightarrow K _{2} SO _{4}+ \underset{{(Green)}}{Cr _{2}\left( SO _{4}\right)_{3}}+ H _{2} O$

Hence, the above reactions indicate the presence of $SO _{3}^{2-}$ ions.