Question

A substance of mass $49.53g$ occupies $1.5c{m}^3$ of volume. The density of the substance (in $gc{m}^{-3}$ ) with correct number of significant figures is

• A. 3.302
• B. 3.300
• C. 3.3
• D. 3.30

Answer 1

Answer: (C)

Mass of the substance $m=49.53g$
Volume of the substance $V=1.5c{m}^3$ Density of the substance $d=\frac{m}{V}$ $\therefore d=\frac{49.53}{1.5}=33.02gc{m}^{-3}$
As $49.53$ has four significant figures whereas $1.5$ has two significant figures. Thus, the value of the density of the substance must have two significant figures. Thus, the density of the substance $d=3.3gc{m}^{-3}$.