A straight wire of length L is bent into a semicircle. It is moved in a uniform magnetic field with speed v with diameter perpendicular to the field. The induced emf between the ends of the wire is

Question

A straight wire of length L is bent into a semicircle. It is moved in a uniform magnetic field with speed v with diameter perpendicular to the field. The induced emf between the ends of the wire is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-11jvkwhldftdtzo0.jpg" /> (A) BLv (B) 2BLv (C) 2π BLv (D) (2 B v L/π )

Tardigrade Admin · Accepted Answer

Induced emf e=Bvl⇒ e=Bv(2 R)=(2 B v L/π )

Q. A straight wire of length $L$ is bent into a semicircle. It is moved in a uniform magnetic field with speed $v$ with diameter perpendicular to the field. The induced emf between the ends of the wire is

$B Lv$

$2 B Lv$

$2 π B Lv$

$\frac{2 B vL}{π}$

Induced emf $e = B v l \Rightarrow e = B v (2 R) = \frac{2 B vL}{π}$

Q. A straight wire of length L is bent into a semicircle. It is moved in a uniform magnetic field with speed v with diameter perpendicular to the field. The induced emf between the ends of the wire is

BLv

2BLv

2πBLv

π2BvL​