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Q. A straight wire of length $L$ is bent into a semicircle. It is moved in a uniform magnetic field with speed $v$ with diameter perpendicular to the field. The induced emf between the ends of the wire is
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NTA AbhyasNTA Abhyas 2022

Solution:

Induced emf $e=Bvl\Rightarrow e=Bv\left(2 R\right)=\frac{2 B v L}{\pi }$