Q.
A straight wire having mass of 1.2kg and length of 1m carries a current of 5A. If the wire is suspended in mid-air by a uniform horizontal magnetic field, then the magnitude of field is
For mid-air suspension the upward force F on wire due to magnetic field B must be balanced by the force due to gravity, then IlB=mg;B=Ilmg
Here, m=1.2kg, g=10ms−2,I=5A, l=1m B=5×11.2×10 =2.4T